Question

if x=y=2 and x^2 =y^2 =4 then what is the value of xy?

Answer 1

x-y=2 ….…(1)

and

x²+y²=4 ………(2)

From equation (1) ,

x=y+2 .………(3)

Putting equation (3) in equation (2) ,we get

(y+2)²+y²=4

=> y²+4y+4+y²=4

=> 2y²+4y=0

Dividing both sides by 2 ,we get

y²+2y=0

Taking y common , we get

y(y+2)=0

Either y=0

or

y+2=0

=>y=-2

Now , putting the above two values of y in equation (3) ,we get

Either

x=0+2

=> x=2

Or

x=(-2)+2

=> x=0

Therefore ,

x=2

y=0

And

x=0

y=-2

Now,

√xy=√(2*0)=0

and

√xy=√(0*(-2))=0

Hence ,the ans is Zero.

Answer 2

Step-by-step explanation:

since you know the value of both X and Y which is

X = 2

Y = 2

X * Y = XY = 2 * 2 = 4

hope it helps... :)