Math, asked by Anonymous, 3 months ago

If x-y=2 and xy=8. Find the value of x^3-y^3.​

Answers

Answered by saddarohithreddy49
3

x = 4

y = 2

x^3 - y^3 =

4^3 + 2^3 =

64 + 8 =

72

Similar questions