Question

If x-y=2 and xy=8,then the value of x^3-y^3 is

Answer 1

Step-by-step explanation:

if x-y=2

xy=8

(x-y)^3=x^3-3x^2y+3xy^2-y^3

so

x^3-y^3=-3xy(x-y)-(x-y)^3

so

-48-8=x^3-y^3

so x^3-y^3=-56