Question

If x+y+2=O,then x cube +y cube +8 equals​

Answer 1

Answer:

Solution

Given that;

x+y+2=0…(1)

To find:

x

3

+y

3

+8=?

Taking cube on both sides of (1):

(x+y+2)

3

=0

x

3

+y

3

+8(x+y+2)(xy+2y+2x)=0.

x

3

+y

3

+8+(0)(xy+2y+2x)=0

x

3

+y

3

+8=0

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Answer 2

Answer:

$O^3 - 3(O-2)(O-x)(O-y)$

Step-by-step explanation:

We know that

$(a + b+c)^3 = a^3 + b^3 + c^3 + 3(a+b)(b+c)(c+a)$

Say, a = x, b = y and c = 2 we get:

$(x + y+2)^3 = x^3 + y^3 + 2^3 + 3(x+y)(y+2)(2+x)\\=> O^3 = x^3 + y^3 + 2^3 + 3(O-2)(O-x)(O-y)\\=> x^3 + y^3 + 2^3 = O^3 - 3(O-2)(O-x)(O-y)\\=> x^3 + y^3 + 8 = O^3 - 3(O-2)(O-x)(O-y)$