Question

if x+y=2 then find the value of x^3+6xy+y^3-8​

Answer 1

Answer:

Step-by-step explanation:

if y=under root x-1/under root x, then 2xdx/dy+y=​

Answer 2

Answer:

Step-by-step explanation:

xpand (x-y)^3 = 2^3

which causes

x^3-y^3-3xy(x-y) = 8

x^3-y^3-6xy = 8