If x+y-2 , then find the value of x³++6xy+y³-8 is ?
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If x = 2 - y
Then ,
x³ + 6xy + y³ - 8 = 0
( 2 - y )³ + 6 ( 2 - y ) y + y³ - 8 = 0
-y³ + 6y² - 12y + 8 - 6y² + 12y + y³ - 8 = 0
0 = 0
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