Question

If x = y + 2, then find the value of y in equation.​

Answer 1

Answer:

x = 32°

y = 30°

Step-by-step explanation:

As per the provided information in the given question, we have :

• ∠POR and ∠QOR are forming a linear pair.
• ∠POR = (2x + 60)°
• ∠QOR = (3x – 40)°

We've to calculate the value of x first. Then we have to calculate the value of y as in the next part of the question.

As, ∠POR and ∠QOR are forming a linear pair, therefore their sum will be 180°.

$\mapsto \sf{ \angle POR + \angle QOR = 180^\circ}$

$\mapsto \sf{ (2x + 60)^\circ + (3x - 40)^\circ= 180^\circ}$

$\mapsto \sf{ 2x^\circ + 60^\circ + 3x^\circ - 40^\circ= 180^\circ}$

$\mapsto \sf{ 5x^\circ + 20^\circ= 180^\circ}$

$\mapsto \sf{ 5x^\circ= 160^\circ}$

$\mapsto \sf{ x^\circ=\cancel{\dfrac{ 160^\circ}{5} }}$

$\mapsto\boxed{ \sf{ x = 32^\circ}}$

Therefore, the value of x is 32°.

Also, according ot the question,

$\qquad \qquad \qquad \sf \Bigg [ x = y + 2 \Bigg ]$

Substitute the value of x.

$\mapsto \sf{ 32^\circ= y + 2}$

$\mapsto \sf{ 32^\circ - 2= y }$

$\mapsto\boxed{ \sf{ y = 30^\circ}}$

Therefore, the value of y is 30° in the equation.

$\rule{200}2$