if x - y = 2 then point x, y is equidistant from 7, 1 and _____
Answers
if x - y = 2 then point x, y is equidistant from 7, 1 and (3 , 5)
Step-by-step explanation:
Let say x - y = 2 and point x, y is equidistant from 7, 1 and a , b
Then a , b will be the image of 7 , 1 along line x - y = 2
x = (7 + a)/2
=> 2x = 7 + a
y = (1 + b)/2
=> 2y = 1 + b
=> 2(x - 2) = 1 + b
=> 2x - 4 = 1 + b
=> 2x = b + 5
=> 7+a = b + 5
=> b = a + 2
Slope of x - y = 2
=> y = x - 2 is 1
Slope of (a , b) & (7, 1) would be - 1
=> (b - 1)/(a - 7) = -1
=> b - 1 = 7 - a
=> b = 8 - a
a + 2 = 8 - a
=> 2a = 6
=> a = 3
b = 5
if x - y = 2 then point x, y is equidistant from 7, 1 and (3 , 5)
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Answer:
Answer is (3,5)
hope it helps!