If x-y=2 then solve x³-y³-6xy
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Answer:
the required is x³- y³ - 6xy =8
Step by step explanation:
Given: x-y =2
To find: what is x³-y³-6xy =??
Solution:
x-y=2
Cubing both side,
(x-y)³ = (2)³
Using algebraic identity,(a-b)³=a³-b³-3ab(a-b)
x³-y³- 3xy(x-y)=8
Substitute the value,
x³-y³-3xy(2) = 8
x³-y³-6xy = 8
Therefore, the required value is x³ - y³ - 6xy = 8
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