if x+y=2,then the value of x^3+6xy+y^3-8 is
(a)1
(b)3
(c)0
(d)5
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Answered by
1
your answer is 0
suppose that x is equal to 1 and Y is equal to 1
suppose that x is equal to 1 and Y is equal to 1
DramaticEye915:
solve plss
Answered by
1
hi!! ..your answer is C
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