Question

If x-y=2 what is x3-y3-6xy=?

Answer 1

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( x - y ) = 2

Cubing on both sides we have

( x - y )³ = 2³

x³ - y³ + 3xy ( x - y ) = 2³

x³ - y³ + 3xy ( x - y ) = 8

x³ - y³ + 3xy ( 2 ) = 8

x³ - y³ + 6xy =8

Answer 2

The required value is $x^3-y^3-6xy=8$.

Step-by-step explanation:

Given : $x-y=2$

To find : What is $x^3-y^3-6xy=?$ ?

Solution :

$x-y=2$

Cubing both side,

$(x-y)^3=(2)^3$

Using algebraic identity, $(a-b)^3=a^3-b^3-3ab(a-b)$

$x^3-y^3-3xy(x-y)=8$

Substitute the value,

$x^3-y^3-3xy(2)=8$

$x^3-y^3-6xy=8$

Therefore, the required value is $x^3-y^3-6xy=8$.

#Learn more

- Simplify: (x - y)^2 + 2(x - y)(x + y) + (x + y)^2.​

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