if x-y =2 where x=5 find the value for x^y y^x/ y^y x^x
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Answer:
x
y
=y
x
…….. (1)
And x=2y ……. (2)
On putting the value of xin equation (2), we get
(2y)
y
=y
2y
2
y
.y
y
=y
y
.y
y
y
y
=2
y
ylny=yln2
∴y=2
Therefore,
x=4
So,
x+y=4+2
x+y=6
Hence, this is the answer.
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