Math, asked by mysicallycrazed, 9 days ago

if x-y =2 where x=5 find the value for x^y y^x/ y^y x^x​

Answers

Answered by kheteshwarkp
1

9/25

Make my answer as brainlist please

Attachments:
Answered by vennampalli1969
1

Answer:

x

y

=y

x

…….. (1)

And x=2y ……. (2)

On putting the value of xin equation (2), we get

(2y)

y

=y

2y

2

y

.y

y

=y

y

.y

y

y

y

=2

y

ylny=yln2

∴y=2

Therefore,

x=4

So,

x+y=4+2

x+y=6

Hence, this is the answer.

please mark me brain list answer I want your help please

Attachments:
Similar questions