if (x-y)²+(x+y)²=0, then what is tha value of y
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(x-y)²+(x+y)² = 0
=> x² + y² - 2xy + x² + y² + 2xy = 0
=> 2x² + 2y² = 0
=> y² = - 2/2x² = -1/x² => y = 1/x
=> x² + y² - 2xy + x² + y² + 2xy = 0
=> 2x² + 2y² = 0
=> y² = - 2/2x² = -1/x² => y = 1/x
gautam7496:
2x²+2y²=0 ke baad samaj me nahi aya
ok thanks
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