Question

if x+y =2019 then what is ( -1)^x + (-1)^y​

Answer 1

Step-by-step explanation:

x+y=2019

Sum of 2 odd nos is even and so of 2 even numbers

So for the given equation to satisfy either of x or y has to be odd and other has to be even

let x be odd and y be even

(-1)^x+(-1)^y

-1 raised to odd power is -1 and -1 raised to even power is 1

And x is odd and y is even

So (-1)^x+(-1)^y =-1+1=0