If x+y=24 and xy=6 then find the value of x^-1+y^-1
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x^-1+y^-1 = 1/x+1/y= (x+y)/xy = 24/6 = 4
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Hey there !!!!!!!!!!!!
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x+y= 24 xy= 6
x⁻¹+y⁻¹ = (1/x)+(1/y)= (x+y)/xy = 24/6 = 4
So, x⁻¹+y⁻¹ = 4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you...........................
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
x+y= 24 xy= 6
x⁻¹+y⁻¹ = (1/x)+(1/y)= (x+y)/xy = 24/6 = 4
So, x⁻¹+y⁻¹ = 4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you...........................
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