Question

If x + y = 29 and xy = 2, find the value of (1) x +y...
(2)x-y
(3)x^4+y^4​

Answer 1

Answer:

(x+y)^2=x^2+y^2+2xy

(29)^2=x^2+y^2+2×2

841-4=x^2+y^2

x^2+y^2=837 .............(1)

(x-y)^2=x^2+y^2-2xy

(x-y)^2=837-4

(x-y)^2=833

x-y=root of 833

HOPE IT HELPS YOU