Question

if x-y=2then point (x,y) is equidistant from(7,1)and__________

Answer 1

if x-y=2then point (x,y) is equidistant from(7,1) and (3 , 5)

Step-by-step explanation:

x - y  = 2

=> y = x - 2

=> m = 1

slope of perpendicular line  = -1

y = -x + c

1 = -7 +c  

=> c = 8

y = -x + 8

y = x - 2

=> -x + 8 =  x - 2

=> 2x = 10

=> x = 5   & y = 3

(5 , 3)  will be mid point of  (7 , 1)  & (x , y)

=> 5 = (7 + x) /2    &  3 = (1 + y)/2

=> x = 3   &  y = 5

if x-y=2then point (x,y) is equidistant from(7,1) and (3 , 5)

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Answer 2

can this question be included in present CBSE X Q's paper of 2019 -20