Question

,if (x+y),(2x+3y) and (3x+5y) are successive terms of arithmetic progression then what is the nth terms of the sequence

Answer 1

Step-by-step explanation:

a = x + y

(2x + 3y) - (x + y) = (3x + 5y) - (2x + 3y)

2x + 3y - x - y = 3x + 5y - 2x - 3y

x + 2y = x + 2y

d = x + 2y

an = a + (n-1)d

$= (x + y) + (n - 1)(x + 2y) \\ = (x + y) + (nx + n2y - x - 2y) \\ = x + y + nx + n2y - x - 2y \\ = nx + n2y - y$

hope you get your answer