Question

if (x/y)=(3/2)^-2÷(3/7)^0;find (x/y)^-3=?​

Answer 1

Step-by-step explanation:

(x/y) = (3/2)^-2 ÷ (3/7)^0

: x/y = (2/3)²

: x/y = 4/9

(x = 4k and y = 9k)

: (x/y)^-3 = (4k/9k)^-3

: (4/9)^-3 = (9/4)³

: 729/64

Hence, (x/y)^-3 = 729/64

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