Math, asked by ankitdas24, 6 months ago

If x/y = (3/2)^-2 ÷ (3/7), find the value of (x/y)^-3.

Answers

Answered by shobhasinghal2325

1

Answer:

19683/19600

Step-by-step explanation:

x/y= (2/3)²÷3/7

=4/9×7/3

=28/27

(x/y)^-3

=(28/27)^-3

=(27/28)^3

=19683/19600

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