Question

if x:y= 3:2,( 4x-2y):(x+y)???​

Answer 1

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Answer 2

The given question is if x:y= 3:2,( 4x-2y):(x+y)???

In the question, the ratio is given as x:y = 3:2

The ratio of two numbers is defined as the number of times one number contains another number.

This ratio can also be written as

$\frac{x}{y} = \frac{3}{2}$

we have to find the value of

$the \: ratio \: of \: (4x - 2y) \: and \: (x + y)$

It is given that x:y = 3:2.

let us assume the value of x and y as x= 3k and y = 2k.

k is a nonzero constant value.

The term given in the question

$(4x - 2y):(x + y)$

can be written in the form of the division as

$\frac{4x - 2y}{x + y}$

let us substitute the value of x and y in the above expression, we get

$\frac{4(3k) - 2(2k)}{(3k + 2k)} \\ = \frac{12k - 4k}{5k} \\ = \frac{8k}{5k} = \frac{8}{5}$

Therefore the final value is

$\frac{8}{5}$

Therefore, the final answer is the ratio of (4x -2y):(x+y)

is 8:5.

# spj2

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