If x:y=3:2and y:z=4:3then the value of x:2zis?
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1:1
Step-by-step explanation:
x:y = 3:2 ; y:z = 4:3
now,
In First case, y= 2 & second case, y= 4
therefore , we a fixed value of y to find out x & z
So, x:y= 3:2
= 3/2 [ LCM of 2 & 4 is 4]
= 3× 2/2×2
= 6/4
=6:4
& y:z = 4:3
hence, x:y:z = 6:4:3
then, x:z = 6:3 = 2:1
So, x: 2z = 2: 2× 1
= 2:2
= 1:1
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