Question

if x:y=3:4 the value of x²y+xy²:x³+y

Answer 1

Answer:

i) Let me consider what you require as: (x²y + xy²) :: (x³ + y³) = ?

ii) From the given data, we have x = (3/4)y or 4x = 3y

iii) (x²y + xy²) :: (x³ + y³) = xy(x + y)/{(x + y)(x² - xy + y²) = (xy)/(x² - xy + y²)

Substituting x = (3/4)y from the above,

(x²y + xy²) :: (x³ + y³) = (3y²/4)/(9y²/16 - 3y²/4 + y²) = 12/(9 - 12 + 16) = 12/13

Thus answer is 12 :: 13

Answer 2

Answer:

12/13

Step-by-step explanation:

x²y+xy²: x³+y³ =  xy ÷ x²-xy +y² = x/y ÷ x²/y²-x/y +1 = 3/4÷1-3/4 +9/16

= 3/4 ÷13/16 = 3/4 x16/13 =  12/13