Math, asked by saiprashanth2580, 1 year ago

if x:y=3:4the value of x²y+xy²:x³+y³ is

Answers

Answered by kindck
7
x/y=3/4
then
x=3
y=4
x²y+xy²/x³+y³
=3²×4+3×4²/3³+4³
=36+48/27+64
=84/91
is 84:91
Answered by chaitragowda
0

Answer:

x=3 y=4

x²y + xy² : x³ + y³

9×4 + 3×16 : 27 + 64

36 + 48 : 91

84 : 91

84/91 = 12/13 = 12 : 13

hint 12 × 7 = 84

13 × 7 = 91

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