Math, asked by aashnaa66brainly, 4 months ago

If x: y = 3: 5, find the ratio 3x + 4y: 8x + 5y



2. If x: y = 8: 9, find the ratio (7x – 4y): 3x + 2y.

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Answers

Answered by Anonymous
6

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Solution:

Given x: y = 3: 5

We can write above equation as

x/y = 3/5

5x = 3y

x = 3y/5

By substituting the value of x in given equation 3x + 4y: 8x + 5y we get,

3x + 4y: 8x + 5y = 3 (3y/5) + 4y: 8 (3y/5) + 5y

= (9y + 20y)/5: (24y + 25y)/5

= 29y/5: 49y/5

= 29y: 49y

= 29: 49

Solution:

Given x: y = 8: 9

We can write above equation as

x/y = 8/9

9x = 8y

x = 8y/9

By substituting the value of x in the given equation (7x – 4y): 3x + 2y we get,

(7x – 4y): 3x + 2y = 7 (8y/9) – 4y: 3 (8y/9) + 2y

= (56y – 36y)/9: 42y/9

= 20y/9: 42y/9

= 20y: 42y

= 20: 42

= 10: 21

Answered by aashnaapal
1

SOLUTION

given that

x :y = 3:5

 \frac{x}{y}  =   \frac{3}{5}

after cross multiplication..

5x = 3y

x =  \frac{3y}{5}  \\  \\ hence-</p><p> 3x + 4y: 8x \\  + 5y = 3 (3y/5) \\  + 4y: 8 (3y/5) + 5y

 \frac{9y+ 20y}{5(24y + 25y)} \div 5

 \frac{9y+ 20y}{5}

 \frac{29y}{5}: \frac{49y}{5}  \\ 29y:49y

29:49 \: answer

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