Question

"if x: y = 3:5, then find (2x + 3y): (5x + 7y).​

Answer 1

Answer:

Hope it helps

Let the constant value=x

x:y=3a:5a

Putting the value of x and y

=(2x+3y):(5x+7y)

=(2*3a+3*5a)+(5*3a+7*5a)

=(6a+15a):(15a+35a)

=(21a):(50a)

=21a:50a

=21:50

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Answer 2

Solution :

Given, x : y = 3 : 5

We have to find (2x + 3y) : (5x + 7y)

From what's given,

→ x/y = 3/5

→ 5x = 3y

→ x = 3y/5

Now,

→ Required ratio = (2x + 3y) : (5x + 7y)

= (2 × 3y/5 + 3y) : (5 × 3y/5 + 7y)

= (6y/5 + 3y)/(3y + 7y)

= [(6y + 15y)/5]/10y

= (21y/5)/10y

= 21y/50y

= 21/50

= 21 : 50

Therefore,

(2x + 3y) : (5x + 7y) = 21 : 50.