Question

if x/y=3/5 then find 3x^2+Y^2/3X^2-Y^2

Answer 1

$\frac{x}{y} = \frac{3}{5} \\ now \\ \frac{3 {x}^{2} + {y}^{2} }{3 {x}^{2} - {y}^{2} } \\ \frac{3 \frac{ {x}^{2} }{ {y}^{2} } + 1 }{3 \frac{ {x}^{2} }{ {y}^{2} } - 1 } \\ \frac{3 \times ( \frac{9}{ 25}) + 1 }{3 \times ( \frac{9}{ 25}) - 1 } \\ = 26$

hope it helps