Math, asked by rajoraneeraj1, 7 months ago

if x/y = 3/7^3 ÷ 3/7^-2, find x/y^2​

Answers

Answered by MAVI200824mdb
0

Step-by-step explanation:

= x/y=3/7^3÷3/7^-2 find x/y^2

 = x\y =3\7^3\div 3\7^ - 2

= then x/y^2 is

 = x\y^2

i hope it will be help full to u

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Answered by nehu215
2

\huge\mathfrak\red{answEr}

x+y=7⋯

x−y=3

x=y+3

Put it in

y+3+y=7

2y+3=7

2y=7−3

2y=4

y= 24 =2

Put y=2 in x+y=7 we get

x=7−y=7−2=5

∴x=5,y=2

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