Math, asked by kingharsh607, 7 months ago

if x+y=3 and x^2+y^2=15 Find (x-y)^2
pls solve ASAP.​

Answers

Answered by raos19656
1

Answer:

 {x}^{2}  -  {y}^{2}  = 15

ye hona chahiye

Step-by-step explanation:

 {x}^{2}  -  {y}^{2}  = 15 \\ (x + y)(x - y) = 15 \\ 3(x - y) = 15 \\ (x - y) =  \frac{15}{3} \\ (x - y) = 5 \\  {(x - y)}^{2}  =  {(5)}^{2}  \\ (x - y) {}^{2}  = 25

Answered by PharohX
1

Step-by-step explanation:

x + y = 3

 {x}^{2}  +  {y}^{2}  = 15

(x + y) {}^{2}  =  {3}^{2}  \\  \\  {x}^{2}  +  {y}^{2}  + 2xy = 9 \\  \\ 15 + 2xy = 9 \\  \\ 2xy = 9 - 15 \\  \\ 2xy =  - 6

(x - y) {}^{2}  =  {x}^{2}  +  {y}^{2}  - 2xy \\  \\  = 15 - ( - 6) \\  \\  = 15 + 6 \\  \\  = 21

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