If x+ y = 3 and x = 3 then y
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Answer:
x3+y3=9 …(i)
x+y=3 …(ii)
Cubing the second equation , we get
(x+y)3=27
x3+y3+3xy(x+y)=27
9+3xy(3)=27
1+xy=3
xy=2
x=2y
From (ii)
2y+y=3
2+y2=3y
y2−3y+2=0
(y−1)(y−2)=0
y=1 (or) y=2
⟹x=2 (or) x=1
Consider any one pair out of (2,1) , (1,2) , as the numbers are same …
So , x4+y4
=(2)4+(1)4
=16+1
=17.
∴x4+y4=17
Hope this answer helps you , Have a good day ahead …
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