If x+y=√3 and x-y=√5 then find the value of X2 +y 2
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Answer:
x2 + y2= 4
Step-by-step explanation:
x = √3 - y
x = √5 + y
therefore, √3 - y = √5 + y
(√3 - √5)/2 = y
x= √3 - (√3 - √5)/2
x= (2√3)/2 - (√3 - √5)/2
x= (√3 + √5)/2
x2 + y2 = [(√3 + √5)/2 ] ^ 2 + [(√3 - √5)/2 ] ^2
= [(3 + 3√15 + 5) + ( 3 - 2√15 + 5)] / 4 = 16 / 4 = 4
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