Question

if x+y = 3 and x² + y² = 5 then xy is ?​

Answer 1

Step-by-step explanation:

x^2+(3-x)^2= 5

x^2+x^2-6x+9=5

2x^2-6x+4=0

x^2-3x+2=0

x^2-2x-x+2=0

(x-1)(x-2)=0

x=1. or x= 2

y= 2 or y=1

xy=2