Question

If x+y=3 and xy=1 find the value of x^2+y^3+xy​

Answer 1

Answer:

Answer :

The values are :

x = 2

y= 1

Given :

The equations are :

x + y = 3

x - y = 1

To Find :

The values of x and y

Solution :

Considering the equations as :

\sf{x + y = 3 \: \: ..........(1)}x+y=3..........(1)

and

\sf{x - y = 1 \: \: ...........(2)}x−y=1...........(2)

Adding the equations (1) and (2) :

\begin{gathered} \sf{x + y + x - y = 3 + 1} \\ \\ \sf{ \implies2x = 4} \\ \\ \implies \sf x = \dfrac{4}{2} \\ \\ \bf \implies x = 2\end{gathered}

x+y+x−y=3+1

⟹2x=4

⟹x=

2

4

⟹x=2

Putting the value of x in (1) :

\begin{gathered} \sf2 + y = 3 \\ \\ \sf{ \implies y = 3 - 2} \\ \\ \implies \bf y = 1\end{gathered}

2+y=3

⟹y=3−2

⟹y=1

Thus x = 2 and y = 1