Question

if x -y= 3 and xy 10 find x2 + y2

Answer 1

$Given \: x - y = 3 \: --(1)$

$and \: xy = 10 \: --(2)$

$\red{ Value \: of \: x^{2} + y^{2} }$

$= (x-y)^{2} + 2xy$

$= 3^{2} + 2 \times 10$

$= 9 + 20$

$= 29$

Therefore.,

$\red{ Value \: of \: x^{2} + y^{2} }\green { = 29}$

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Answer 2

Answer:

Givenx−y=3−−(1)

and \: xy = 10 \: --(2)andxy=10−−(2)

\red{ Value \: of \: x^{2} + y^{2} }Valueofx2+y2

= (x-y)^{2} + 2xy=(x−y)2+2xy

= 3^{2} + 2 \times 10=32+2×10

= 9 + 20=9+20

= 29=29

Therefore.,

\red{ Value \: of \: x^{2} + y^{2} }\green { = 29}Valueofx2+y2=29