If x+y=3 and xy=2, find x cube +y cube
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Step-by-step explanation:
it is given that, x + y = 3 and xy = 2
firstly, (x+y) ^2 = x^2 + y^2 + 2xy
put the above values in it,
(3)^2 = x^2 + y^2 + 2(2)
x^2 + y^2 = 9-4
x^2 + y^2 = 3
now
x^3 + y^3 = (x + y)(x^2 - xy + y^2)
= (3)(3-2)
x^3 + y^3 = 3
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