Math, asked by 999kranthipriya, 1 month ago

if x=y-3 that gives x/y-x+1/y=1​

Answers

Answered by chandansuthar
1

Answer:

first of all

Step-by-step explanation:

x=y-3-------(1)

where x/y -(x+1)/y=1

(x-x+1)/y=1

1/y=1

y=1

put this value in so called first equation

we get x value

x=1-3

x=-2

so x=-2 and y=1

Answered by poonambahiram010
0

Step-by-step explanation:

x/y -x + 1/y = 1

x/y -xy / y +1/y =1

x-xy+1/y = 1

x-xy+1 = y __1

substitute x= y-3 in the equation 1

y-3 - (y-3)y +1 =y

y-3 -y^2-3y +1 = y

-y^2 -2y -2 = y

y^2 +y+2y +2 =0

y^2 +3y +2 =0

y^2 +2y +y +2 =0

y (y+2 ) +1 (y+2) =0

y+2 =0 or y+1 =0

y =-2 or y= -1

case 1

put y= -2 in eq 1

x- x(-2) +1 = -2

x+2x +1 +2 =0

3x = -3

x= -1

(x,y) = (-1,-2)

case 2

put y = -1 in eq 1

x-x(-1) +1 = -1

x+2x = -1 -1

3x = -2

x = -2/3

(x,y) = ( -2/3 , -1 )

Similar questions