if x=y-3 that gives x/y-x+1/y=1
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Answered by
1
Answer:
first of all
Step-by-step explanation:
x=y-3-------(1)
where x/y -(x+1)/y=1
(x-x+1)/y=1
1/y=1
y=1
put this value in so called first equation
we get x value
x=1-3
x=-2
so x=-2 and y=1
Answered by
0
Step-by-step explanation:
x/y -x + 1/y = 1
x/y -xy / y +1/y =1
x-xy+1/y = 1
x-xy+1 = y __1
substitute x= y-3 in the equation 1
y-3 - (y-3)y +1 =y
y-3 -y^2-3y +1 = y
-y^2 -2y -2 = y
y^2 +y+2y +2 =0
y^2 +3y +2 =0
y^2 +2y +y +2 =0
y (y+2 ) +1 (y+2) =0
y+2 =0 or y+1 =0
y =-2 or y= -1
case 1
put y= -2 in eq 1
x- x(-2) +1 = -2
x+2x +1 +2 =0
3x = -3
x= -1
(x,y) = (-1,-2)
case 2
put y = -1 in eq 1
x-x(-1) +1 = -1
x+2x = -1 -1
3x = -2
x = -2/3
(x,y) = ( -2/3 , -1 )
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