If x + y = 3, then find the value of x^3 + y^3 – 27 + 9xy
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0 [zero]
Step-by-step explanation:
--> (x³ + y³) = (x + y)*(x²-xy-y²) = 3*(x²-xy-y²)
--> 3*(x²-xy-y²) = 3x²-3xy-3y²
--> (3x²-3xy-3y² )+9xy = 3*(x+y)² = 27
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