Question

if (x+y)³-(x-y)³-6y(x²-y²)=ky² ,then k =?​

Answer 1

Let's solve for k.

$(x+y)^{3} -(x-y)^{3} -6y(x^{2} -y^{2} )=ky^{2}$

Step 1: First of all we need to flip the following equation like this ⇒

$ky^{2} = 8y^{3}$

Step 2: Then we have to divide both sides by y².

$\frac{ky^{2}}{y^{2} } = \frac{8y^{3}}{y^{2} }$

∴ k = 8y

∴ The answer is ⇒ k = 8y.