If (x + y)3 - ( x - y )3 - 6y (x2 - y2) = ky2, then k =
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( x + y)³ -( x -y)³ -6y(x² - y² ) = Ky²
we know,
a³ - b³ = (a - b)( a² + ab + b²)
(x + y)³ -(x - y)³ = (x + y - x + y){(x +y)² + ( x -y)² + (x +y)(x -y) }
=( 2y ) { 2x² + 2y² + x² - y²)
= 2y ( 3x² + y²)
put this in above ,
2y ( 3x² + y²) -6y( x² - y²) = Ky²
6x²y +2y³ -6x²y +6y³ = Ky²
8y³ = Ky²
K = 8y
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