Math, asked by aryan183946, 1 year ago

if x+y=3, x²+y²=5 , then xy is​


aryan183946: answer me
Nikki2504: Given, x+y=3 and x^2+y^2=5. Use the identity (a+b)^2= a^2+b^2+2ab. So (x+y)^2=x^2+y^2+2xy. Now, x+y=3 and x^2+y^2=5. Therefore, 3^2=5^2+2xy = 9=25+2xy =
Nikki2504: = 9-25=2xy
Nikki2504: -16=2xy
Nikki2504: xy=-16/2
Nikki2504: xy=8
aryan183946: you are wrong
aryan183946: on kki
aryan183946: nikki
aryan183946: you are totally wrong

Answers

Answered by Santhosekumar
46

Answer:

2 is the answer!!!

Step-by-step explanation:

(a+b)²=A square+b square + 2 ab

3² = 5+2xy

2xy = 4

xy = 2

Make me brainilist if you like it :)

Answered by sahadebesh7
28

Answer:

2

Step-by-step explanation:

(x + y)^{2} = x^{2} + y^{2} + 2xy

or, 3^{2} = 5 + 2xy

or, 9 - 5 = 2xy

or, xy = 4/2

or, xy = 2


aryan183946: wrong answer it is not a option
aryan183946: do fast and wright
aryan183946: wrong wrong wrong
sahadebesh7: Is it now correct?
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