If x-y = 3 ,xy =10 find the value of x^3-y^3 please tell me fast
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Given:
x-y = 3 and xy = 10
To find: x^3- y^3
x-y = 3 ......equ(1)
(x-y)^2 = 9
or, x^2 + y^2 -2xy = 9
or, x^2 + y^2 - 20 = 9
or, x^2 + y^2 = 29 ..... equ(2)
from identity,
x^3 - y^3 = (x-y)(x^+xy+y^2)
using equations 1 & 2
x^3 - y^3 = 3(29 +10)
or, x^3 - y^3 = 3(39)
or, x^3 - y^3 = 117
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