if x+y=3 xy=2 find value of x³-y³
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Step-by-step explanation:
7 is the required answer...refer to the attachment...
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Step-by-step explanation:
Given:- x+y=3 ; xy=2
So (x-y)²=(x+y)²-4xy
(x-y)²=3²-4(2)
(x-y)²=9-8
x-y=√1
x-y=1.......................eq(1)
(x+y)²=x²+y²+2xy
3²=x²+y²+2(2)
9-4=x²+y²
x²+y²=5.................eq(2)
To find :- x³-y³
x³-y³=(x-y)(x²+y²+xy)
=1(5+2)=7
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