if x=y=33 and z=34 then find x^3+y^3+z^3-3xyz
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0
Answer:
It may help you. You can do it by using one more process, but that will be more complex.
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Step-by-step explanation:
given that x=y=33 and z=34
so substitute the values of x,y and z
[33]^3+[33]^3+[34]^3-3[33][33][34]
= 35937+35937+39304-111078
= 100
100% correct answer
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