Math, asked by pushpa9801019299, 2 months ago

if x=y=33 and z=34 then find x^3+y^3+z^3-3xyz​

Answers

Answered by niloypaul2day
0

Answer:

It may help you. You can do it by using one more process, but that will be more complex.

Attachments:
Answered by thayiradhika
1

Answer:

Step-by-step explanation:

given that x=y=33 and z=34

so substitute the values of x,y and z

[33]^3+[33]^3+[34]^3-3[33][33][34]

= 35937+35937+39304-111078

= 100

100% correct answer

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