if x= y,3x-y=4 and x+y+z=6 then find value of 'Z'
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Answered by
11
if x=y
3x-y=4
putting the value of x
3y-y=4
2y=4
y=2
now x=y
so y=2
now x+y+z=6
2+2+z=6
4+z=6
z=6-4
z=2
hence the value of z is 2
3x-y=4
putting the value of x
3y-y=4
2y=4
y=2
now x=y
so y=2
now x+y+z=6
2+2+z=6
4+z=6
z=6-4
z=2
hence the value of z is 2
Answered by
4
x=y
3 x-y=4
3y-y=4
2y=4
y=2
x+y+z=6
y+y+z=6
2+2+z=6
4+z=6
z=6-4
z=2
x=y=z=2
3 x-y=4
3y-y=4
2y=4
y=2
x+y+z=6
y+y+z=6
2+2+z=6
4+z=6
z=6-4
z=2
x=y=z=2
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