Question

If x+y+4=0 find the value of (x3+y3-12xy+64)

Answer 1

.......,...............

Answer 2

$x + y + 4 = 0 \\ x = - 4 - y \\ {x}^{3} + {y}^{3} - 12xy + 64 \\ putting \: the \: value \: of \: x \\ {( - 4 - y)}^{3} + {y}^{3} - 12( - 4 - y)y + 64$
y=0
x=-4