Question

If x+y+4 = 0 find the value of (x3+y3-12xy+64)

Answer 1

Hey mate here we go

$first \: write \: the \: equation \\ x + y + 4 = 0............(1) \\ {x}^{3} + {y}^{3} - 12xy + 64 .........(2)\\ lets \: rewrite \: the \: equation \: (1) \\ x + y = - 4 \\ now \: that \: equation \: is \: in \: the \: form \: of \\ {( x+ y)}^{3} = {x}^{3}+ {y}^{3} + 3 {x}^{2}y +3 x{y}^{2} ...(3) \: \\ put \: x + y = - 4 \: \: \: in \: eq \: \: (3) \\ ( { - 4)}^{3} = - 4 \times - 4 \times - 4 = - 64 \\ = - 64 \: \: \: is \: ur \: ans$

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Answer 2

Answer:

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