Question

if x+y+4=0then find the value of x^3+y^3-12xy+64​

Answer 1

Answer:

The answer to the question Is zero

Answer 2

Answer:

0

Step-by-step explanation:

x+y=-4

cubing on both sides

(x+y)^3 = - 64

x^3+y^3+3xy(x+y) = - 64

⇒x^3+y^3-12xy= -64  [∵x+y =-4]

∴x^3+y^3-12xy+64=0