Question

if x: y=4:5 find the value of (3X+4y): (6X+ 7y)

Answer 1

$\frac{x}{y} = \frac{4z}{5z} \: z \: is \: varible \: \\ \frac{3x + 4y}{6x + 7y}$

$\frac{12z + 20z}{24z + 35z} \\ \frac{32z}{59z} \\ \\ = \frac{32}{59}$

Answer 2

Answer:

Let x= 4k and y= 5k ( * denote multiplication )

(3x+4y):(6x+7y)

(3*4k+4*5k):(6*4k+7*5k)

(12k+20k):(24k+35k)

32k:59k

32:59.