If x+y=4 & xy=5 find value of (x3+y3)
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cubing the first eqn we get
x^3+y^3+3xy(x+y)=64
replacing values of x+y and xy
x^3+y^3= 64-3*5*4
x^3+y^3=4
x^3+y^3+3xy(x+y)=64
replacing values of x+y and xy
x^3+y^3= 64-3*5*4
x^3+y^3=4
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