Question

if x-y=4 and x+y=6 ,find x^2+y^2

Answer 1

Your answer is ---

Given,

x - y = 4 ......(1)

x + y = 6 .....(2)

adding equation (1) & (2) , we get

2x = 10

=> x = 5

put this value in equation (2), we get

5 + y = 6

=> y = 6 - 5

=> y = 1

Now,
xy = 5 × 1 = 5 ....(3).

So,

${x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy \\ \\ = {6}^{2} - 2 \times 5 \\ \\ = 36 - 10 \\ \\ = 26$

【 Hope it helps you 】

Answer 2

Heya!

______
Here given : x-y=4 --------(1)
and. x+y=6 --------(2)

Add both equation ,we get
⇒2x=10
⇒x=5

Put the value of x in equation 1
⇒x-y=4
⇒y=1

Now find ⇒x²+y²
⇒5²+1²
⇒25+1
⇒26

Hope this helps you ☺☺